Math 9th Ex 2.1 new book | Notes Punjab
Math 9th Ex 2.1 new book

Math 9th Ex 2.1 | New book

Math 9th Ex 2.1 | New book

Math 9th Ex 2.1 new book 2025 will be completely solved. Scientific notation and ordinary notation will be explained.

A number is scientific notation is written as: $$a\;\times\;10^n,\;where\\1\leq a<10\;\;and\;\;n\in\mathbb{Z}$$

After the solution of this exercise, we will completely solve exercise 2.2, exercise 2.3, exercise 2.4 and review exercise 2 also. In this series, we will also check how to find the log of any positive number not only with the help of calculator but also by using logarithmic table. We will concentrate on  how to check mantissa properly with the help of log table. At the end of this series, we will solve all the MCQs in full detail and also try to understand all the concepts of whole chapter 2 math class 9 new book. Calculation will be according to the 4 decimal places.

Lets start Math 9th Ex 2.1 New book.

Q1 Express the numbers in scientific notation:

(i) 2000000
$$2.0\;\times\;10^6$$
(ii) 48900
$$4.89\;\times10^5$$
(iii) 0.0042
$$4.2\;\times10^{-3}$$
(iv) 0.0000009
$$9.0\;\times\;10^{-7}$$
(v) $$73\;\times\;10^3$$

Question is important because it looks like as its in scientific notation but actually its not in Scientific notation. To clear this concept check the definition of scientific notation in the introduction.

$$73\;\times\;10^3\\=\;7.3\;\times\;10^3\;\times\;10^1\\=\;7.3\;\times\;10^{3+1}\\=\;7.3\;\times\;10^4$$
(vi) $$0.65\;\times\;10^2$$

Question is not in Scientific notation. Kindly check  the definition of scientific notation in the introduction.

$$=\;0.65\;\times\;10^2\;\\=\;6.5\;\times\;10^2\;\times\;10^{-1}\\=\;6.5\;\times\;10^{2-1}\\=\;6.5\;\times\;10^1$$

Q2 Express the following numbers in ordinary notation:

(i) $$8.04\;\times\;10^2$$
= 804
(ii) $$=3\;\times\;10^5$$
= 300000
(iii) $$=1.5\;\times\;10^{-2}$$
= 0.015
(iv) $$=1.77\;\times\;10^7$$
= 17700000
(v) $$=5.5\;\times\;10^{-6}$$
= 0.0000055
(vi) $$=4\;\times\;10^{-5}$$
= 0.00004

Q3 $$The\;speed\;of\;light\;is\;\\approximately\;3\;\times\;10^8\\meters\;per\;second.\\Express\;it\;in\\s\mathrm{tand}ard\;form\;.$$

$$3\;\times\;10^8\;m\;s^{-1}\\=\;300000000\;m\;s^{-1}$$

Q4 The circumference of earth at the equator is about 40075000 meters. Express in scientific notation.

$$40075000\;m\\=\;4.0075\;\times\;10^7\;m$$

Q5 $$The\;diameter\;of\;Mars\;is\\6.7779\;\times\;10^3\;km.\;Express\\it\;in\;s\tan dard\;form$$

$$6.7779\;\times\;10^3\;km\\6777.9\;km$$

Q6 $$Diameter\;of\;Earth\;is\;about\\1.2756\times10^4\;km.\;Express\\it\;in\;s\tan dard\;form.$$

$$1.2756\times10^4\;km\\12756\;km$$

You tube New book Grade 9 Math Exercise 2.1

New book Math class 9 Exercise 1.1

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