10th Class Math Chapter 3 MCQs fbise Solution

10th Class Math Chapter 3 MCQs fbise Solution

10th Class Math Chapter 3 MCQs fbise Solved Questions

Looking for the authentic 10th Class Math Chapter 3 MCQs fbise ? In this post, we provide the solved multiple-choice questions based on the new textbook syllabus.

10 Math Chapter 3 MCQs Federal Board

Tick the correct option.

(i)

If

$$\begin{bmatrix}5&3\\2&9\end{bmatrix}^t=\begin{bmatrix}5&\frac x2\\3&9\end{bmatrix}$$

then x =

(a) 6

(b) 4

(c) -6

(d) -4

Correct option is (b)

========================================

(ii)

If

$$I_3=\begin{bmatrix}y&0&x\\0&z&0\\x&0&1\end{bmatrix}$$

then:

(a) y = x = 1

(b) x = z = 0

(c) x = z = 1

(d) y = z = 1, x = 0

Correct option is (d)

========================================

(iii)

Additive inverse of unit matrix of order 2, is:

$$(a)\;\begin{bmatrix}0&0\\0&0\end{bmatrix}\\(b)\;\begin{bmatrix}-1&0\\0&-1\end{bmatrix}\\(c)\;\begin{bmatrix}0&1\\1&0\end{bmatrix}\\(d)\;\begin{bmatrix}1&0\\0&-1\end{bmatrix}$$

Correct option is (b)

========================================

(iv)

Multiplicative inverse of a null matrix of order 2, is:

$$(a)\;\begin{bmatrix}0&0\\0&0\end{bmatrix}\\(b)\;\begin{bmatrix}0\\0\end{bmatrix}\\(c)\;\begin{bmatrix}0&0\end{bmatrix}\\(d)\;impossible$$

Correct option is (d)

========================================

(v)

A is a symmetric matrix if:

$$(a)\;A^t\neq A\\(b)\;{(A^t)}^t\neq-A\\(c)\;{(A^t)}^t=-A\\(d)\;{(A^t)}^t=A^t$$

Correct option is (d)

========================================

(vi)

$$\left[\frac12\right]+\begin{bmatrix}0\\0\end{bmatrix}=$$

$$(a)\;\left[\frac12\right]\\(b)\;\begin{bmatrix}1\\2\end{bmatrix}\\(c)\;\left[\frac12\begin{array}{c}0\\0\end{array}\right]\\(d)\;impossible$$

Correct option is (d)

========================================

(vii)

Order of a matrix A is 1-by-2 and order of matrix B is 2-by-3 then order of AB is:

(a) 1-by-3

(b) 3-by-1

(c) 2-by-2

(d) 3-by-2

Correct option is (a)

========================================

(viii)

If AB = B, then A = ____

$$(a)\;I\\(b)\;A^{-1}\\(c)\;B\\(d)\;B^{-1}$$

Correct option is (a)

========================================

(ix)

$$\begin{bmatrix}15\\25\end{bmatrix}\times\begin{bmatrix}3&2\end{bmatrix}=$$

$$(a)\;\begin{bmatrix}95\end{bmatrix}\\(b)\;\begin{bmatrix}45\\50\end{bmatrix}\\(c)\;\begin{bmatrix}45&50\end{bmatrix}\\(d)\;\begin{bmatrix}45&30\\75&50\end{bmatrix}$$

Correct option is (d)

========================================

(x)

If

$$T=-1,\;then\;T^{-1}=$$

(a) -T

(b) adj T

(c) -adj T

(d) T

Correct option is (c)

========================================

(xi)

Matrix equation for y + x = 144 + y and x + 2y = x + 13 is:

$$(a)\;\begin{bmatrix}1&1\\1&2\end{bmatrix}\times\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}144\\13\end{bmatrix}\\(b)\;\begin{bmatrix}1&0\\1&2\end{bmatrix}\times\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}144\\13\end{bmatrix}$$

$$(a)\;\begin{bmatrix}1&0\\0&2\end{bmatrix}\times\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}144\\13\end{bmatrix}\\(b)\;\begin{bmatrix}1&0\\0&2\end{bmatrix}\times\begin{bmatrix}y\\x\end{bmatrix}=\begin{bmatrix}144\\13\end{bmatrix}$$

Correct option is (c)

========================================

(xii)

The matrix of coefficients for x-y = 3, is:

$$(a)\;\begin{bmatrix}3\end{bmatrix}\\(b)\;\begin{bmatrix}1&-1\end{bmatrix}\\(c)\;\begin{bmatrix}x\\y\end{bmatrix}\\(d)\;\begin{bmatrix}1\\-1\end{bmatrix}$$

Correct option is (b)

========================================

(xiii)

[1      2] [3] =

$$(a)\;\begin{bmatrix}3&6\end{bmatrix}\\(b)\;\begin{bmatrix}3\\6\end{bmatrix}\\(c)\;\begin{bmatrix}5\end{bmatrix}\\(d)\;impossible$$

Correct option is (d)

========================================

(xiv)

If A and B are two matrices, conformable for the product 

$$AB\;then\;{(AB)}^t=$$

$$(a)\;A^tB^t\\(b)\;{(BA)}^t\\(c)\;B^tA^t\\(d)\;AB$$

Correct option is (c)

========================================

(xv)

If 

$$\begin{bmatrix}-3&5\\-3&x-1\end{bmatrix}$$

is singular matrix, then x =

(a) 4

(b) 6

(c) -6

(d) -4

Correct option is (b)

========================================

(xvi)

If

$$adj\;A=\begin{bmatrix}5&6\\2&3\end{bmatrix}\;then\;\vert A\vert=$$

$$(a)\;\vert\;adj\;A\;\vert\\(b)\;\vert\;A^t\;\vert\\(c)\;\vert\;-A\;\vert\\(d)\;all\;a,\;b,\;c$$

Correct option is (d)

========================================


Check! Some important links below

Math Class 10 New Book Federal Board Chapter 4 MCQs

10th Class Math Videos

Home Page

Leave a Comment

Comments

No comments yet. Why don’t you start the discussion?

Leave a Reply

Your email address will not be published. Required fields are marked *