9th class math fbise Exercise 6.2 Q7 solution
Class9 Math Ex6.2 q7 NBF

9th class math fbise Exercise 6.2 Q7 solution

 

9th class math fbise Exercise 6.2 Q7 solution

9th Class Math fbise Exercise 6.2 Q7 Solved

Class9 Math Ex6.2 q7  Find the perimeter and area of a half-circle if its diameter is 12 cm.

Step-by-Step Solution

1. Find the Radius

Given that the diameter is 12 cm, we can find the radius (r) using:

r=diameter2=122=6 cmr = \frac{\text{diameter}}{2} = \frac{12}{2} = 6 \text{ cm}

2. Calculate the Area

The area of a full circle is given by:-

A=πr2A = \pi r^2

Since we need the area of a half-circle, we divide by 2:

Ahalf-circle=12×π×62A_{\text{half-circle}} = \frac{1}{2} \times \pi \times 6^2 A=12×π×36A = \frac{1}{2} \times \pi \times 36 A=18π56.52 cm2A = 18\pi \approx 56.52 \text{ cm}^2

3. Calculate the Perimeter

The perimeter of a half-circle includes the curved edge (half of the circumference of a full circle) and the straight-line diameter:

  • The circumference of a full circle is:
    C=2πr=2×π×6=12π 
     
  • The curved part of the half-circle is half of this:
    12π2=6π 
     
  • Adding the straight-line diameter (12 cm):
    P=6π+12P = 6\pi + 12
     

    Implies

    P18.84+12=30.84 cmP \approx 18.84 + 12 = 30.84 \text{ cm}

Final Answer

  • Area = 56.52 cm²
  • Perimeter = 30.84 cm

For detailed solution click on the following link:-

 

Exercise 6.2 Question 8 math class 9 Federal board

You tube channel federal board 9th

Home page Notespunjab.com

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